Y=10^2+3x-4

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Solution for Y=10^2+3x-4 equation: 



=10^2+3Y-4

We move all terms to the left:

-(10^2+3Y-4)=0

We get rid of parentheses

-3Y+4-10^2=0

We add all the numbers together, and all the variables

-3Y-96=0

We move all terms containing Y to the left, all other terms to the right

-3Y=96

Y=96/-3

Y=-32

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